40=5/18x^2

Solution for 40=5/18x^2 equation:

40=5/18x^2

We move all terms to the left:

40-(5/18x^2)=0


Domain of the equation: 18x^2)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

-5/18x^2+40=0

We multiply all the terms by the denominator


40*18x^2-5=0

Wy multiply elements

720x^2-5=0

a = 720; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·720·(-5)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*720}=\frac{-120}{1440}
=-1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*720}=\frac{120}{1440}
=1/12
$